(2x2=11)(x2+14)

Solution for (2x2=11)(x2+14) equation:

(2x^2=11)(x2+14)

We move all terms to the left:

(2x^2-(11)(x2+14))=0

We add all the numbers together, and all the variables

(2x^2-11(+x^2+14))=0


We calculate terms in parentheses: +(2x^2-11(+x^2+14)), so:

2x^2-11(+x^2+14)

We multiply parentheses

2x^2-11x^2-154

We add all the numbers together, and all the variables

-9x^2-154

Back to the equation:

+(-9x^2-154)


We get rid of parentheses

-9x^2-154=0

a = -9; b = 0; c = -154;
Δ = b2-4ac
Δ = 02-4·(-9)·(-154)
Δ = -5544
Delta is less than zero, so there is no solution for the equation