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(2x=11)+(9x-5)
We move all terms to the left:
(2x-(11)+(9x-5))=0
We calculate terms in parentheses: +(2x-11+(9x-5)), so:We get rid of parentheses
2x-11+(9x-5)
determiningTheFunctionDomain 2x+(9x-5)-11
We get rid of parentheses
2x+9x-5-11
We add all the numbers together, and all the variables
11x-16
Back to the equation:
+(11x-16)
11x-16=0
We move all terms containing x to the left, all other terms to the right
11x=16
x=16/11
x=1+5/11
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