(2x=30)+(6x-12)

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Solution for (2x=30)+(6x-12) equation: 



(2x=30)+(6x-12)

We move all terms to the left:

(2x-(30)+(6x-12))=0



We calculate terms in parentheses: +(2x-30+(6x-12)), so:

2x-30+(6x-12)

determiningTheFunctionDomain
2x+(6x-12)-30

We get rid of parentheses

2x+6x-12-30

We add all the numbers together, and all the variables

8x-42

Back to the equation:

+(8x-42)



We get rid of parentheses

8x-42=0

We move all terms containing x to the left, all other terms to the right

8x=42

x=42/8

x=5+1/4

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