(2x=5)(x-4)=0

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Solution for (2x=5)(x-4)=0 equation: 



(2x=5)(x-4)=0

We move all terms to the left:

(2x-(5)(x-4))=0



We calculate terms in parentheses: +(2x-5(x-4)), so:

2x-5(x-4)

We multiply parentheses

2x-5x+20

We add all the numbers together, and all the variables

-3x+20

Back to the equation:

+(-3x+20)



We get rid of parentheses

-3x+20=0

We move all terms containing x to the left, all other terms to the right

-3x=-20

x=-20/-3

x=6+2/3

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