(2y)/(y+2)=6-4/(y+2)

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Solution for (2y)/(y+2)=6-4/(y+2) equation: 



(2y)/(y+2)=6-4/(y+2)

We move all terms to the left:

(2y)/(y+2)-(6-4/(y+2))=0



Domain of the equation: (y+2)!=0

We move all terms containing y to the left, all other terms to the right

y!=-2

y∈R





Domain of the equation: (y+2))!=0

y∈R



We calculate fractions


6y^2/((y+2)*(y+2)))+(-(-4*(y+8))/((y+2)*(y+2)))=0



We calculate terms in parentheses: -(-4*(y+8))/((y+2)*(y+2))), so:

-4*(y+8))/((y+2)*(y+2))

We multiply all the terms by the denominator


-4*(y+8))

We multiply parentheses

-4y-

We add all the numbers together, and all the variables

-4y

Back to the equation:

-(-4y)



We get rid of parentheses

6y^2/((y+2)*(y+2)))+(+4y=0

We multiply all the terms by the denominator


6y^2+4y*((y+2)*(y+2)))+(=0

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