(2y+1)(7+y)=0

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Solution for (2y+1)(7+y)=0 equation:


Simplifying
(2y + 1)(7 + y) = 0

Reorder the terms:
(1 + 2y)(7 + y) = 0

Multiply (1 + 2y) * (7 + y)
(1(7 + y) + 2y * (7 + y)) = 0
((7 * 1 + y * 1) + 2y * (7 + y)) = 0
((7 + 1y) + 2y * (7 + y)) = 0
(7 + 1y + (7 * 2y + y * 2y)) = 0
(7 + 1y + (14y + 2y2)) = 0

Combine like terms: 1y + 14y = 15y
(7 + 15y + 2y2) = 0

Solving
7 + 15y + 2y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(7 + y)(1 + 2y) = 0

Subproblem 1

Set the factor '(7 + y)' equal to zero and attempt to solve: Simplifying 7 + y = 0 Solving 7 + y = 0 Move all terms containing y to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + y = 0 + -7 Combine like terms: 7 + -7 = 0 0 + y = 0 + -7 y = 0 + -7 Combine like terms: 0 + -7 = -7 y = -7 Simplifying y = -7

Subproblem 2

Set the factor '(1 + 2y)' equal to zero and attempt to solve: Simplifying 1 + 2y = 0 Solving 1 + 2y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 2y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 2y = 0 + -1 2y = 0 + -1 Combine like terms: 0 + -1 = -1 2y = -1 Divide each side by '2'. y = -0.5 Simplifying y = -0.5

Solution

y = {-7, -0.5}

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