(2y+1)(y+6)=2y(y+4)

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Solution for (2y+1)(y+6)=2y(y+4) equation: 



(2y+1)(y+6)=2y(y+4)

We move all terms to the left:

(2y+1)(y+6)-(2y(y+4))=0

We multiply parentheses ..

(+2y^2+12y+y+6)-(2y(y+4))=0



We calculate terms in parentheses: -(2y(y+4)), so:

2y(y+4)

We multiply parentheses

2y^2+8y

Back to the equation:

-(2y^2+8y)



We get rid of parentheses

2y^2-2y^2+12y+y-8y+6=0

We add all the numbers together, and all the variables

5y+6=0

We move all terms containing y to the left, all other terms to the right

5y=-6

y=-6/5

y=-1+1/5

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