(2y+1)(y-1)=

Solution for (2y+1)(y-1)= equation:

Simplifying
(2y + 1)(y + -1) = 0

Reorder the terms:
(1 + 2y)(y + -1) = 0

Reorder the terms:
(1 + 2y)(-1 + y) = 0

Multiply (1 + 2y) * (-1 + y)
(1(-1 + y) + 2y * (-1 + y)) = 0
((-1 * 1 + y * 1) + 2y * (-1 + y)) = 0
((-1 + 1y) + 2y * (-1 + y)) = 0
(-1 + 1y + (-1 * 2y + y * 2y)) = 0
(-1 + 1y + (-2y + 2y2)) = 0

Combine like terms: 1y + -2y = -1y
(-1 + -1y + 2y2) = 0

Solving
-1 + -1y + 2y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-1 + -2y)(1 + -1y) = 0

Subproblem 1
Set the factor '(-1 + -2y)' equal to zero and attempt to solve:

Simplifying
-1 + -2y = 0

Solving
-1 + -2y = 0

Move all terms containing y to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -2y = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -2y = 0 + 1
-2y = 0 + 1

Combine like terms: 0 + 1 = 1
-2y = 1

Divide each side by '-2'.
y = -0.5

Simplifying
y = -0.5
Subproblem 2
Set the factor '(1 + -1y)' equal to zero and attempt to solve:

Simplifying
1 + -1y = 0

Solving
1 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1y = 0 + -1
-1y = 0 + -1

Combine like terms: 0 + -1 = -1
-1y = -1

Divide each side by '-1'.
y = 1

Simplifying
y = 1
Solution
y = {-0.5, 1}