(2y+1)+2(3y-1)+2y=19

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Solution for (2y+1)+2(3y-1)+2y=19 equation: 



(2y+1)+2(3y-1)+2y=19

We move all terms to the left:

(2y+1)+2(3y-1)+2y-(19)=0

We add all the numbers together, and all the variables

2y+(2y+1)+2(3y-1)-19=0

We multiply parentheses

2y+(2y+1)+6y-2-19=0

We get rid of parentheses

2y+2y+6y+1-2-19=0

We add all the numbers together, and all the variables

10y-20=0

We move all terms containing y to the left, all other terms to the right

10y=20

y=20/10

y=2

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