(2y+1)+2(3y-1)=19

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Solution for (2y+1)+2(3y-1)=19 equation: 



(2y+1)+2(3y-1)=19

We move all terms to the left:

(2y+1)+2(3y-1)-(19)=0

We multiply parentheses

(2y+1)+6y-2-19=0

We get rid of parentheses

2y+6y+1-2-19=0

We add all the numbers together, and all the variables

8y-20=0

We move all terms containing y to the left, all other terms to the right

8y=20

y=20/8

y=2+1/2

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