(2y+1)-(3y-2)=0

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Solution for (2y+1)-(3y-2)=0 equation: 



(2y+1)-(3y-2)=0

We get rid of parentheses

2y-3y+1+2=0

We add all the numbers together, and all the variables

-1y+3=0

We move all terms containing y to the left, all other terms to the right

-y=-3

y=-3/-1

y=+3

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