(2y+1)2-(2y-1)2=16

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Solution for (2y+1)2-(2y-1)2=16 equation: 


Simplifying
(2y + 1) * 2 + -1(2y + -1) * 2 = 16

Reorder the terms:
(1 + 2y) * 2 + -1(2y + -1) * 2 = 16

Reorder the terms for easier multiplication:
2(1 + 2y) + -1(2y + -1) * 2 = 16
(1 * 2 + 2y * 2) + -1(2y + -1) * 2 = 16
(2 + 4y) + -1(2y + -1) * 2 = 16

Reorder the terms:
2 + 4y + -1(-1 + 2y) * 2 = 16

Reorder the terms for easier multiplication:
2 + 4y + -1 * 2(-1 + 2y) = 16

Multiply -1 * 2
2 + 4y + -2(-1 + 2y) = 16
2 + 4y + (-1 * -2 + 2y * -2) = 16
2 + 4y + (2 + -4y) = 16

Reorder the terms:
2 + 2 + 4y + -4y = 16

Combine like terms: 2 + 2 = 4
4 + 4y + -4y = 16

Combine like terms: 4y + -4y = 0
4 + 0 = 16
4 = 16

Solving
4 = 16

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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