(2y+1)=(4y-5)

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Solution for (2y+1)=(4y-5) equation: 



(2y+1)=(4y-5)

We move all terms to the left:

(2y+1)-((4y-5))=0

We get rid of parentheses

2y-((4y-5))+1=0



We calculate terms in parentheses: -((4y-5)), so:

(4y-5)

We get rid of parentheses

4y-5

Back to the equation:

-(4y-5)



We get rid of parentheses

2y-4y+5+1=0

We add all the numbers together, and all the variables

-2y+6=0

We move all terms containing y to the left, all other terms to the right

-2y=-6

y=-6/-2

y=+3

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