(2y+1)=(5y-3)

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Solution for (2y+1)=(5y-3) equation: 



(2y+1)=(5y-3)

We move all terms to the left:

(2y+1)-((5y-3))=0

We get rid of parentheses

2y-((5y-3))+1=0



We calculate terms in parentheses: -((5y-3)), so:

(5y-3)

We get rid of parentheses

5y-3

Back to the equation:

-(5y-3)



We get rid of parentheses

2y-5y+3+1=0

We add all the numbers together, and all the variables

-3y+4=0

We move all terms containing y to the left, all other terms to the right

-3y=-4

y=-4/-3

y=1+1/3

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