(2y+17)(7y+5)=0

Solution for (2y+17)(7y+5)=0 equation:

(2y+17)(7y+5)=0

We multiply parentheses ..

(+14y^2+10y+119y+85)=0

We get rid of parentheses

14y^2+10y+119y+85=0

We add all the numbers together, and all the variables

14y^2+129y+85=0

a = 14; b = 129; c = +85;
Δ = b2-4ac
Δ = 1292-4·14·85
Δ = 11881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11881}=109$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(129)-109}{2*14}=\frac{-238}{28}
=-8+1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(129)+109}{2*14}=\frac{-20}{28}
=-5/7
$