(2y+19)(7y+10)=0

Solution for (2y+19)(7y+10)=0 equation:

(2y+19)(7y+10)=0

We multiply parentheses ..

(+14y^2+20y+133y+190)=0

We get rid of parentheses

14y^2+20y+133y+190=0

We add all the numbers together, and all the variables

14y^2+153y+190=0

a = 14; b = 153; c = +190;
Δ = b2-4ac
Δ = 1532-4·14·190
Δ = 12769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12769}=113$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(153)-113}{2*14}=\frac{-266}{28}
=-9+1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(153)+113}{2*14}=\frac{-40}{28}
=-1+3/7
$