(2y+2)+(4n+4)=

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Solution for (2y+2)+(4n+4)= equation:


Simplifying
(2y + 2) + (4n + 4) = 0

Reorder the terms:
(2 + 2y) + (4n + 4) = 0

Remove parenthesis around (2 + 2y)
2 + 2y + (4n + 4) = 0

Reorder the terms:
2 + 2y + (4 + 4n) = 0

Remove parenthesis around (4 + 4n)
2 + 2y + 4 + 4n = 0

Reorder the terms:
2 + 4 + 4n + 2y = 0

Combine like terms: 2 + 4 = 6
6 + 4n + 2y = 0

Solving
6 + 4n + 2y = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + 4n + -6 + 2y = 0 + -6

Reorder the terms:
6 + -6 + 4n + 2y = 0 + -6

Combine like terms: 6 + -6 = 0
0 + 4n + 2y = 0 + -6
4n + 2y = 0 + -6

Combine like terms: 0 + -6 = -6
4n + 2y = -6

Add '-2y' to each side of the equation.
4n + 2y + -2y = -6 + -2y

Combine like terms: 2y + -2y = 0
4n + 0 = -6 + -2y
4n = -6 + -2y

Divide each side by '4'.
n = -1.5 + -0.5y

Simplifying
n = -1.5 + -0.5y

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