(2y+22)=(3y-2)

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Solution for (2y+22)=(3y-2) equation: 



(2y+22)=(3y-2)

We move all terms to the left:

(2y+22)-((3y-2))=0

We get rid of parentheses

2y-((3y-2))+22=0



We calculate terms in parentheses: -((3y-2)), so:

(3y-2)

We get rid of parentheses

3y-2

Back to the equation:

-(3y-2)



We get rid of parentheses

2y-3y+2+22=0

We add all the numbers together, and all the variables

-1y+24=0

We move all terms containing y to the left, all other terms to the right

-y=-24

y=-24/-1

y=+24

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