(2y+23)=(4y+8)

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Solution for (2y+23)=(4y+8) equation: 



(2y+23)=(4y+8)

We move all terms to the left:

(2y+23)-((4y+8))=0

We get rid of parentheses

2y-((4y+8))+23=0



We calculate terms in parentheses: -((4y+8)), so:

(4y+8)

We get rid of parentheses

4y+8

Back to the equation:

-(4y+8)



We get rid of parentheses

2y-4y-8+23=0

We add all the numbers together, and all the variables

-2y+15=0

We move all terms containing y to the left, all other terms to the right

-2y=-15

y=-15/-2

y=7+1/2

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