(2y+3)(6y+7)=(3y+2)(4y+5)

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Solution for (2y+3)(6y+7)=(3y+2)(4y+5) equation: 



(2y+3)(6y+7)=(3y+2)(4y+5)

We move all terms to the left:

(2y+3)(6y+7)-((3y+2)(4y+5))=0

We multiply parentheses ..

(+12y^2+14y+18y+21)-((3y+2)(4y+5))=0



We calculate terms in parentheses: -((3y+2)(4y+5)), so:

(3y+2)(4y+5)

We multiply parentheses ..

(+12y^2+15y+8y+10)

We get rid of parentheses

12y^2+15y+8y+10

We add all the numbers together, and all the variables

12y^2+23y+10

Back to the equation:

-(12y^2+23y+10)



We get rid of parentheses

12y^2-12y^2+14y+18y-23y+21-10=0

We add all the numbers together, and all the variables

9y+11=0

We move all terms containing y to the left, all other terms to the right

9y=-11

y=-11/9

y=-1+2/9

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