(2y+3)/3=(5y-1)/2

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Solution for (2y+3)/3=(5y-1)/2 equation: 



(2y+3)/3=(5y-1)/2

We move all terms to the left:

(2y+3)/3-((5y-1)/2)=0

We calculate fractions


2y/()+(-((5y-1)*3)/()=0



We calculate terms in parentheses: +(-((5y-1)*3)/(), so:

-((5y-1)*3)/(

We multiply all the terms by the denominator


-((5y-1)*3)



We calculate terms in parentheses: -((5y-1)*3), so:

(5y-1)*3

We multiply parentheses

15y-3

Back to the equation:

-(15y-3)



We get rid of parentheses

-15y+3

Back to the equation:

+(-15y+3)



We get rid of parentheses

2y/()-15y+3=0

We multiply all the terms by the denominator


2y-15y*()+3*()=0

We add all the numbers together, and all the variables

2y-15y*()=0

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