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(2y+3)/y-9=2/7
We move all terms to the left:
(2y+3)/y-9-(2/7)=0
Domain of the equation: y!=0We add all the numbers together, and all the variables
y∈R
(2y+3)/y-9-(+2/7)=0
We get rid of parentheses
(2y+3)/y-9-2/7=0
We calculate fractions
(14y+21)/7y+(-2y)/7y-9=0
We multiply all the terms by the denominator
(14y+21)+(-2y)-9*7y=0
Wy multiply elements
(14y+21)+(-2y)-63y=0
We get rid of parentheses
14y-2y-63y+21=0
We add all the numbers together, and all the variables
-51y+21=0
We move all terms containing y to the left, all other terms to the right
-51y=-21
y=-21/-51
y=7/17
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