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(2y+3)=(5y-3)
We move all terms to the left:
(2y+3)-((5y-3))=0
We get rid of parentheses
2y-((5y-3))+3=0
We calculate terms in parentheses: -((5y-3)), so:We get rid of parentheses
(5y-3)
We get rid of parentheses
5y-3
Back to the equation:
-(5y-3)
2y-5y+3+3=0
We add all the numbers together, and all the variables
-3y+6=0
We move all terms containing y to the left, all other terms to the right
-3y=-6
y=-6/-3
y=+2
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