(2y+32)-(3y-2)=4

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Solution for (2y+32)-(3y-2)=4 equation: 



(2y+32)-(3y-2)=4

We move all terms to the left:

(2y+32)-(3y-2)-(4)=0

We get rid of parentheses

2y-3y+32+2-4=0

We add all the numbers together, and all the variables

-1y+30=0

We move all terms containing y to the left, all other terms to the right

-y=-30

y=-30/-1

y=+30

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