(2y+38)=(7y-17)

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Solution for (2y+38)=(7y-17) equation: 



(2y+38)=(7y-17)

We move all terms to the left:

(2y+38)-((7y-17))=0

We get rid of parentheses

2y-((7y-17))+38=0



We calculate terms in parentheses: -((7y-17)), so:

(7y-17)

We get rid of parentheses

7y-17

Back to the equation:

-(7y-17)



We get rid of parentheses

2y-7y+17+38=0

We add all the numbers together, and all the variables

-5y+55=0

We move all terms containing y to the left, all other terms to the right

-5y=-55

y=-55/-5

y=+11

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