(2y+4)+(3y-65)=y

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Solution for (2y+4)+(3y-65)=y equation: 



(2y+4)+(3y-65)=y

We move all terms to the left:

(2y+4)+(3y-65)-(y)=0

We add all the numbers together, and all the variables

-1y+(2y+4)+(3y-65)=0

We get rid of parentheses

-1y+2y+3y+4-65=0

We add all the numbers together, and all the variables

4y-61=0

We move all terms containing y to the left, all other terms to the right

4y=61

y=61/4

y=15+1/4

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