(2y+4)+(5b+1)=

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Solution for (2y+4)+(5b+1)= equation:


Simplifying
(2y + 4) + (5b + 1) = 0

Reorder the terms:
(4 + 2y) + (5b + 1) = 0

Remove parenthesis around (4 + 2y)
4 + 2y + (5b + 1) = 0

Reorder the terms:
4 + 2y + (1 + 5b) = 0

Remove parenthesis around (1 + 5b)
4 + 2y + 1 + 5b = 0

Reorder the terms:
4 + 1 + 5b + 2y = 0

Combine like terms: 4 + 1 = 5
5 + 5b + 2y = 0

Solving
5 + 5b + 2y = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + 5b + -5 + 2y = 0 + -5

Reorder the terms:
5 + -5 + 5b + 2y = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 5b + 2y = 0 + -5
5b + 2y = 0 + -5

Combine like terms: 0 + -5 = -5
5b + 2y = -5

Add '-2y' to each side of the equation.
5b + 2y + -2y = -5 + -2y

Combine like terms: 2y + -2y = 0
5b + 0 = -5 + -2y
5b = -5 + -2y

Divide each side by '5'.
b = -1 + -0.4y

Simplifying
b = -1 + -0.4y

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