(2y+4)+3y=48

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Solution for (2y+4)+3y=48 equation: 



(2y+4)+3y=48

We move all terms to the left:

(2y+4)+3y-(48)=0

We add all the numbers together, and all the variables

3y+(2y+4)-48=0

We get rid of parentheses

3y+2y+4-48=0

We add all the numbers together, and all the variables

5y-44=0

We move all terms containing y to the left, all other terms to the right

5y=44

y=44/5

y=8+4/5

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