(2y+4)/12=(y+4)/7

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Solution for (2y+4)/12=(y+4)/7 equation:



(2y+4)/12=(y+4)/7
We move all terms to the left:
(2y+4)/12-((y+4)/7)=0
We calculate fractions
2y/()+(-((y+4)*12)/()=0
We calculate terms in parentheses: +(-((y+4)*12)/(), so:
-((y+4)*12)/(
We multiply all the terms by the denominator
-((y+4)*12)
We calculate terms in parentheses: -((y+4)*12), so:
(y+4)*12
We multiply parentheses
12y+48
Back to the equation:
-(12y+48)
We get rid of parentheses
-12y-48
Back to the equation:
+(-12y-48)
We get rid of parentheses
2y/()-12y-48=0
We multiply all the terms by the denominator
2y-12y*()-48*()=0
We add all the numbers together, and all the variables
2y-12y*()=0

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