(2y+4)/12=(y+4)/7

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Solution for (2y+4)/12=(y+4)/7 equation: 



(2y+4)/12=(y+4)/7

We move all terms to the left:

(2y+4)/12-((y+4)/7)=0

We calculate fractions


2y/()+(-((y+4)*12)/()=0



We calculate terms in parentheses: +(-((y+4)*12)/(), so:

-((y+4)*12)/(

We multiply all the terms by the denominator


-((y+4)*12)



We calculate terms in parentheses: -((y+4)*12), so:

(y+4)*12

We multiply parentheses

12y+48

Back to the equation:

-(12y+48)



We get rid of parentheses

-12y-48

Back to the equation:

+(-12y-48)



We get rid of parentheses

2y/()-12y-48=0

We multiply all the terms by the denominator


2y-12y*()-48*()=0

We add all the numbers together, and all the variables

2y-12y*()=0

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