(2y+5)(1+y)=0

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Solution for (2y+5)(1+y)=0 equation:


Simplifying
(2y + 5)(1 + y) = 0

Reorder the terms:
(5 + 2y)(1 + y) = 0

Multiply (5 + 2y) * (1 + y)
(5(1 + y) + 2y * (1 + y)) = 0
((1 * 5 + y * 5) + 2y * (1 + y)) = 0
((5 + 5y) + 2y * (1 + y)) = 0
(5 + 5y + (1 * 2y + y * 2y)) = 0
(5 + 5y + (2y + 2y2)) = 0

Combine like terms: 5y + 2y = 7y
(5 + 7y + 2y2) = 0

Solving
5 + 7y + 2y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(5 + 2y)(1 + y) = 0

Subproblem 1

Set the factor '(5 + 2y)' equal to zero and attempt to solve: Simplifying 5 + 2y = 0 Solving 5 + 2y = 0 Move all terms containing y to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + 2y = 0 + -5 Combine like terms: 5 + -5 = 0 0 + 2y = 0 + -5 2y = 0 + -5 Combine like terms: 0 + -5 = -5 2y = -5 Divide each side by '2'. y = -2.5 Simplifying y = -2.5

Subproblem 2

Set the factor '(1 + y)' equal to zero and attempt to solve: Simplifying 1 + y = 0 Solving 1 + y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + y = 0 + -1 y = 0 + -1 Combine like terms: 0 + -1 = -1 y = -1 Simplifying y = -1

Solution

y = {-2.5, -1}

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