(2y+5)(y+2)=-3(2y+5)

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Solution for (2y+5)(y+2)=-3(2y+5) equation: 


Simplifying
(2y + 5)(y + 2) = -3(2y + 5)

Reorder the terms:
(5 + 2y)(y + 2) = -3(2y + 5)

Reorder the terms:
(5 + 2y)(2 + y) = -3(2y + 5)

Multiply (5 + 2y) * (2 + y)
(5(2 + y) + 2y * (2 + y)) = -3(2y + 5)
((2 * 5 + y * 5) + 2y * (2 + y)) = -3(2y + 5)
((10 + 5y) + 2y * (2 + y)) = -3(2y + 5)
(10 + 5y + (2 * 2y + y * 2y)) = -3(2y + 5)
(10 + 5y + (4y + 2y2)) = -3(2y + 5)

Combine like terms: 5y + 4y = 9y
(10 + 9y + 2y2) = -3(2y + 5)

Reorder the terms:
10 + 9y + 2y2 = -3(5 + 2y)
10 + 9y + 2y2 = (5 * -3 + 2y * -3)
10 + 9y + 2y2 = (-15 + -6y)

Solving
10 + 9y + 2y2 = -15 + -6y

Solving for variable 'y'.

Reorder the terms:
10 + 15 + 9y + 6y + 2y2 = -15 + -6y + 15 + 6y

Combine like terms: 10 + 15 = 25
25 + 9y + 6y + 2y2 = -15 + -6y + 15 + 6y

Combine like terms: 9y + 6y = 15y
25 + 15y + 2y2 = -15 + -6y + 15 + 6y

Reorder the terms:
25 + 15y + 2y2 = -15 + 15 + -6y + 6y

Combine like terms: -15 + 15 = 0
25 + 15y + 2y2 = 0 + -6y + 6y
25 + 15y + 2y2 = -6y + 6y

Combine like terms: -6y + 6y = 0
25 + 15y + 2y2 = 0

Factor a trinomial.
(5 + y)(5 + 2y) = 0


Subproblem 1
Set the factor '(5 + y)' equal to zero and attempt to solve:

Simplifying
5 + y = 0

Solving
5 + y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + y = 0 + -5

Combine like terms: 5 + -5 = 0
0 + y = 0 + -5
y = 0 + -5

Combine like terms: 0 + -5 = -5
y = -5

Simplifying
y = -5

Subproblem 2
Set the factor '(5 + 2y)' equal to zero and attempt to solve:

Simplifying
5 + 2y = 0

Solving
5 + 2y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + 2y = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 2y = 0 + -5
2y = 0 + -5

Combine like terms: 0 + -5 = -5
2y = -5

Divide each side by '2'.
y = -2.5

Simplifying
y = -2.5
Solution
y = {-5, -2.5}

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