(2y+5)*(y+5)=150

Solution for (2y+5)*(y+5)=150 equation:

(2y+5)(y+5)=150

We move all terms to the left:

(2y+5)(y+5)-(150)=0

We multiply parentheses ..

(+2y^2+10y+5y+25)-150=0

We get rid of parentheses

2y^2+10y+5y+25-150=0

We add all the numbers together, and all the variables

2y^2+15y-125=0

a = 2; b = 15; c = -125;
Δ = b2-4ac
Δ = 152-4·2·(-125)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-35}{2*2}=\frac{-50}{4}
=-12+1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+35}{2*2}=\frac{20}{4}
=5
$