(2y+6)(y+14)=0

Solution for (2y+6)(y+14)=0 equation:

(2y+6)(y+14)=0

We multiply parentheses ..

(+2y^2+28y+6y+84)=0

We get rid of parentheses

2y^2+28y+6y+84=0

We add all the numbers together, and all the variables

2y^2+34y+84=0

a = 2; b = 34; c = +84;
Δ = b2-4ac
Δ = 342-4·2·84
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-22}{2*2}=\frac{-56}{4}
=-14
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+22}{2*2}=\frac{-12}{4}
=-3
$