(2y+6)(y+3)=0

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Solution for (2y+6)(y+3)=0 equation: 



(2y+6)(y+3)=0

We multiply parentheses ..

(+2y^2+6y+6y+18)=0

We get rid of parentheses

2y^2+6y+6y+18=0

We add all the numbers together, and all the variables

2y^2+12y+18=0

a = 2; b = 12; c = +18;
Δ = b2-4ac
Δ = 122-4·2·18
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{-12}{4}=-3$

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