(2y+9)=(16y-6)+(9y+5)

Solution for (2y+9)=(16y-6)+(9y+5) equation:

(2y+9)=(16y-6)+(9y+5)

We move all terms to the left:

(2y+9)-((16y-6)+(9y+5))=0

We get rid of parentheses

2y-((16y-6)+(9y+5))+9=0


We calculate terms in parentheses: -((16y-6)+(9y+5)), so:

(16y-6)+(9y+5)

We get rid of parentheses

16y+9y-6+5

We add all the numbers together, and all the variables

25y-1

Back to the equation:

-(25y-1)


We get rid of parentheses

2y-25y+1+9=0

We add all the numbers together, and all the variables

-23y+10=0

We move all terms containing y to the left, all other terms to the right

-23y=-10

y=-10/-23

y=10/23