(2y+9)=(16y-6)+(9y+5)

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Solution for (2y+9)=(16y-6)+(9y+5) equation:



(2y+9)=(16y-6)+(9y+5)
We move all terms to the left:
(2y+9)-((16y-6)+(9y+5))=0
We get rid of parentheses
2y-((16y-6)+(9y+5))+9=0
We calculate terms in parentheses: -((16y-6)+(9y+5)), so:
(16y-6)+(9y+5)
We get rid of parentheses
16y+9y-6+5
We add all the numbers together, and all the variables
25y-1
Back to the equation:
-(25y-1)
We get rid of parentheses
2y-25y+1+9=0
We add all the numbers together, and all the variables
-23y+10=0
We move all terms containing y to the left, all other terms to the right
-23y=-10
y=-10/-23
y=10/23

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