(2y+y)(2y-1)=0

Solution for (2y+y)(2y-1)=0 equation:

(2y+y)(2y-1)=0

We add all the numbers together, and all the variables

(+3y)(2y-1)=0

We multiply parentheses ..

(+6y^2-3y)=0

We get rid of parentheses

6y^2-3y=0

a = 6; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·6·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*6}=\frac{0}{12}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*6}=\frac{6}{12}
=1/2
$