(2y-1)-6(y-2)+3=6

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Solution for (2y-1)-6(y-2)+3=6 equation: 



(2y-1)-6(y-2)+3=6

We move all terms to the left:

(2y-1)-6(y-2)+3-(6)=0

We add all the numbers together, and all the variables

(2y-1)-6(y-2)-3=0

We multiply parentheses

(2y-1)-6y+12-3=0

We get rid of parentheses

2y-6y-1+12-3=0

We add all the numbers together, and all the variables

-4y+8=0

We move all terms containing y to the left, all other terms to the right

-4y=-8

y=-8/-4

y=+2

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