(2y-1)/3=(y-1)/2

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Solution for (2y-1)/3=(y-1)/2 equation: 



(2y-1)/3=(y-1)/2

We move all terms to the left:

(2y-1)/3-((y-1)/2)=0

We calculate fractions


2y/()+(-((y-1)*3)/()=0



We calculate terms in parentheses: +(-((y-1)*3)/(), so:

-((y-1)*3)/(

We multiply all the terms by the denominator


-((y-1)*3)



We calculate terms in parentheses: -((y-1)*3), so:

(y-1)*3

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)



We get rid of parentheses

-3y+3

Back to the equation:

+(-3y+3)



We get rid of parentheses

2y/()-3y+3=0

We multiply all the terms by the denominator


2y-3y*()+3*()=0

We add all the numbers together, and all the variables

2y-3y*()=0

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