(2y-1)=((4/3)y+8)

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Solution for (2y-1)=((4/3)y+8) equation: 



(2y-1)=((4/3)y+8)

We move all terms to the left:

(2y-1)-(((4/3)y+8))=0



Domain of the equation: 3)y+8))!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(2y-1)-(((+4/3)y+8))=0

We get rid of parentheses

2y-(((+4/3)y+8))-1=0

We multiply all the terms by the denominator


2y*3)y+8))-(((-1*3)y+8))+4=0

We add all the numbers together, and all the variables

2y*3)y+8))-(((-3)y+8))+4=0

Wy multiply elements

6y^2-3)y+8))+4=0

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