(2y-12)/(3y-12)=0

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Solution for (2y-12)/(3y-12)=0 equation: 



(2y-12)/(3y-12)=0



Domain of the equation: (3y-12)!=0

We move all terms containing y to the left, all other terms to the right

3y!=12

y!=12/3

y!=4

y∈R



We multiply all the terms by the denominator


(2y-12)=0

We get rid of parentheses

2y-12=0

We move all terms containing y to the left, all other terms to the right

2y=12

y=12/2

y=6

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