(2y-23)=(4y+17)

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Solution for (2y-23)=(4y+17) equation: 



(2y-23)=(4y+17)

We move all terms to the left:

(2y-23)-((4y+17))=0

We get rid of parentheses

2y-((4y+17))-23=0



We calculate terms in parentheses: -((4y+17)), so:

(4y+17)

We get rid of parentheses

4y+17

Back to the equation:

-(4y+17)



We get rid of parentheses

2y-4y-17-23=0

We add all the numbers together, and all the variables

-2y-40=0

We move all terms containing y to the left, all other terms to the right

-2y=40

y=40/-2

y=-20

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