(2y-3)(2y+3)=0

Solution for (2y-3)(2y+3)=0 equation:

Simplifying
(2y + -3)(2y + 3) = 0

Reorder the terms:
(-3 + 2y)(2y + 3) = 0

Reorder the terms:
(-3 + 2y)(3 + 2y) = 0

Multiply (-3 + 2y) * (3 + 2y)
(-3(3 + 2y) + 2y * (3 + 2y)) = 0
((3 * -3 + 2y * -3) + 2y * (3 + 2y)) = 0
((-9 + -6y) + 2y * (3 + 2y)) = 0
(-9 + -6y + (3 * 2y + 2y * 2y)) = 0
(-9 + -6y + (6y + 4y2)) = 0

Combine like terms: -6y + 6y = 0
(-9 + 0 + 4y2) = 0
(-9 + 4y2) = 0

Solving
-9 + 4y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + 4y2 = 0 + 9

Combine like terms: -9 + 9 = 0
0 + 4y2 = 0 + 9
4y2 = 0 + 9

Combine like terms: 0 + 9 = 9
4y2 = 9

Divide each side by '4'.
y2 = 2.25

Simplifying
y2 = 2.25

Take the square root of each side:
y = {-1.5, 1.5}