(2y-3)(2y+3)=16

Solution for (2y-3)(2y+3)=16 equation:

Simplifying
(2y + -3)(2y + 3) = 16

Reorder the terms:
(-3 + 2y)(2y + 3) = 16

Reorder the terms:
(-3 + 2y)(3 + 2y) = 16

Multiply (-3 + 2y) * (3 + 2y)
(-3(3 + 2y) + 2y * (3 + 2y)) = 16
((3 * -3 + 2y * -3) + 2y * (3 + 2y)) = 16
((-9 + -6y) + 2y * (3 + 2y)) = 16
(-9 + -6y + (3 * 2y + 2y * 2y)) = 16
(-9 + -6y + (6y + 4y2)) = 16

Combine like terms: -6y + 6y = 0
(-9 + 0 + 4y2) = 16
(-9 + 4y2) = 16

Solving
-9 + 4y2 = 16

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + 4y2 = 16 + 9

Combine like terms: -9 + 9 = 0
0 + 4y2 = 16 + 9
4y2 = 16 + 9

Combine like terms: 16 + 9 = 25
4y2 = 25

Divide each side by '4'.
y2 = 6.25

Simplifying
y2 = 6.25

Take the square root of each side:
y = {-2.5, 2.5}