(2y-3)(y+1)=-4(2y-3)

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Solution for (2y-3)(y+1)=-4(2y-3) equation:


Simplifying
(2y + -3)(y + 1) = -4(2y + -3)

Reorder the terms:
(-3 + 2y)(y + 1) = -4(2y + -3)

Reorder the terms:
(-3 + 2y)(1 + y) = -4(2y + -3)

Multiply (-3 + 2y) * (1 + y)
(-3(1 + y) + 2y * (1 + y)) = -4(2y + -3)
((1 * -3 + y * -3) + 2y * (1 + y)) = -4(2y + -3)
((-3 + -3y) + 2y * (1 + y)) = -4(2y + -3)
(-3 + -3y + (1 * 2y + y * 2y)) = -4(2y + -3)
(-3 + -3y + (2y + 2y2)) = -4(2y + -3)

Combine like terms: -3y + 2y = -1y
(-3 + -1y + 2y2) = -4(2y + -3)

Reorder the terms:
-3 + -1y + 2y2 = -4(-3 + 2y)
-3 + -1y + 2y2 = (-3 * -4 + 2y * -4)
-3 + -1y + 2y2 = (12 + -8y)

Solving
-3 + -1y + 2y2 = 12 + -8y

Solving for variable 'y'.

Reorder the terms:
-3 + -12 + -1y + 8y + 2y2 = 12 + -8y + -12 + 8y

Combine like terms: -3 + -12 = -15
-15 + -1y + 8y + 2y2 = 12 + -8y + -12 + 8y

Combine like terms: -1y + 8y = 7y
-15 + 7y + 2y2 = 12 + -8y + -12 + 8y

Reorder the terms:
-15 + 7y + 2y2 = 12 + -12 + -8y + 8y

Combine like terms: 12 + -12 = 0
-15 + 7y + 2y2 = 0 + -8y + 8y
-15 + 7y + 2y2 = -8y + 8y

Combine like terms: -8y + 8y = 0
-15 + 7y + 2y2 = 0

Factor a trinomial.
(-5 + -1y)(3 + -2y) = 0

Subproblem 1

Set the factor '(-5 + -1y)' equal to zero and attempt to solve: Simplifying -5 + -1y = 0 Solving -5 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1y = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1y = 0 + 5 -1y = 0 + 5 Combine like terms: 0 + 5 = 5 -1y = 5 Divide each side by '-1'. y = -5 Simplifying y = -5

Subproblem 2

Set the factor '(3 + -2y)' equal to zero and attempt to solve: Simplifying 3 + -2y = 0 Solving 3 + -2y = 0 Move all terms containing y to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -2y = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -2y = 0 + -3 -2y = 0 + -3 Combine like terms: 0 + -3 = -3 -2y = -3 Divide each side by '-2'. y = 1.5 Simplifying y = 1.5

Solution

y = {-5, 1.5}

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