(2y-3)=(7y+5)

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Solution for (2y-3)=(7y+5) equation: 



(2y-3)=(7y+5)

We move all terms to the left:

(2y-3)-((7y+5))=0

We get rid of parentheses

2y-((7y+5))-3=0



We calculate terms in parentheses: -((7y+5)), so:

(7y+5)

We get rid of parentheses

7y+5

Back to the equation:

-(7y+5)



We get rid of parentheses

2y-7y-5-3=0

We add all the numbers together, and all the variables

-5y-8=0

We move all terms containing y to the left, all other terms to the right

-5y=8

y=8/-5

y=-1+3/5

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