(2y-3)=(7y-1)

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Solution for (2y-3)=(7y-1) equation: 



(2y-3)=(7y-1)

We move all terms to the left:

(2y-3)-((7y-1))=0

We get rid of parentheses

2y-((7y-1))-3=0



We calculate terms in parentheses: -((7y-1)), so:

(7y-1)

We get rid of parentheses

7y-1

Back to the equation:

-(7y-1)



We get rid of parentheses

2y-7y+1-3=0

We add all the numbers together, and all the variables

-5y-2=0

We move all terms containing y to the left, all other terms to the right

-5y=2

y=2/-5

y=-2/5

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