(2y-3)=-9-9+3y+6

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Solution for (2y-3)=-9-9+3y+6 equation: 



(2y-3)=-9-9+3y+6

We move all terms to the left:

(2y-3)-(-9-9+3y+6)=0

We add all the numbers together, and all the variables

(2y-3)-(3y-12)=0

We get rid of parentheses

2y-3y-3+12=0

We add all the numbers together, and all the variables

-1y+9=0

We move all terms containing y to the left, all other terms to the right

-y=-9

y=-9/-1

y=+9

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