(2y-40)+(y+43)+(y+21)=180

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Solution for (2y-40)+(y+43)+(y+21)=180 equation: 



(2y-40)+(y+43)+(y+21)=180

We move all terms to the left:

(2y-40)+(y+43)+(y+21)-(180)=0

We get rid of parentheses

2y+y+y-40+43+21-180=0

We add all the numbers together, and all the variables

4y-156=0

We move all terms containing y to the left, all other terms to the right

4y=156

y=156/4

y=39

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