(2y-5)(2y+5)=0

Solution for (2y-5)(2y+5)=0 equation:

Simplifying
(2y + -5)(2y + 5) = 0

Reorder the terms:
(-5 + 2y)(2y + 5) = 0

Reorder the terms:
(-5 + 2y)(5 + 2y) = 0

Multiply (-5 + 2y) * (5 + 2y)
(-5(5 + 2y) + 2y * (5 + 2y)) = 0
((5 * -5 + 2y * -5) + 2y * (5 + 2y)) = 0
((-25 + -10y) + 2y * (5 + 2y)) = 0
(-25 + -10y + (5 * 2y + 2y * 2y)) = 0
(-25 + -10y + (10y + 4y2)) = 0

Combine like terms: -10y + 10y = 0
(-25 + 0 + 4y2) = 0
(-25 + 4y2) = 0

Solving
-25 + 4y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '25' to each side of the equation.
-25 + 25 + 4y2 = 0 + 25

Combine like terms: -25 + 25 = 0
0 + 4y2 = 0 + 25
4y2 = 0 + 25

Combine like terms: 0 + 25 = 25
4y2 = 25

Divide each side by '4'.
y2 = 6.25

Simplifying
y2 = 6.25

Take the square root of each side:
y = {-2.5, 2.5}