(2y-5)-8=(3-y)+3

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Solution for (2y-5)-8=(3-y)+3 equation: 



(2y-5)-8=(3-y)+3

We move all terms to the left:

(2y-5)-8-((3-y)+3)=0

We add all the numbers together, and all the variables

(2y-5)-((-1y+3)+3)-8=0

We get rid of parentheses

2y-((-1y+3)+3)-5-8=0



We calculate terms in parentheses: -((-1y+3)+3), so:

(-1y+3)+3

We get rid of parentheses

-1y+3+3

We add all the numbers together, and all the variables

-1y+6

Back to the equation:

-(-1y+6)



We add all the numbers together, and all the variables

2y-(-1y+6)-13=0

We get rid of parentheses

2y+1y-6-13=0

We add all the numbers together, and all the variables

3y-19=0

We move all terms containing y to the left, all other terms to the right

3y=19

y=19/3

y=6+1/3

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